School curriculum· 25 min· 21 questions
Learn first: Common and decimal fractions
The real numbers fill every point of the number line “without gaps”: each point corresponds to one number and each number to one point. Historically the number system grew in stages: natural numbers for counting, integers for subtraction, rationals for division, and irrationals for taking roots and measuring lengths. Exam questions often ask you to sort numbers into sets, convert a recurring decimal into a fraction, compare numbers with roots and decide whether a number is rational.
N ⊂ Z ⊂ Q ⊂ R
√n (n natural) is rational only when n is a perfect square: √16 = 4, but √5 is irrational. Likewise ∛n is rational only when n is a perfect cube.
A rational number is a terminating or recurring decimal; an irrational number is an infinite non-recurring decimal
Why is a rational number recurring? In long division of p by q the remainders can only be 0, 1, …, q − 1. Within q steps a remainder repeats, and from then on the digits repeat: 1/7 = 0.(142857).
A fraction in lowest terms gives a terminating decimal only if its denominator has no prime factors other than 2 and 5: 3/8 = 0.375, but 1/3 = 0.(3).
Converting a recurring decimal to a fraction:
Purely recurring: 0.(ab) = ab/99; mixed: 0.a(b) = (ab − a)/90
Rule: the numerator is “the digits after the point minus the part before the repeating block”; the denominator has as many nines as there are digits in the block, followed by as many zeros as digits before it.
Convert 0.(27) and 0.2(3) to fractions.
Suppose √2 = p/q in lowest terms. Then p² = 2q², so p² is even and hence p is even: p = 2k. Then 4k² = 2q², q² = 2k², so q is even too. Both even — the fraction can be simplified, contradicting the assumption. Therefore √2 is not rational.
This is proof by contradiction: assume the opposite and reach a contradiction. In the same way √3, √5 and the root of any natural number that is not a perfect square are shown to be irrational.
Is (√3 − 1)² + 2√3 rational?
To compare expressions with roots, move factors under the root or square both (for positive numbers the order is preserved):
a√b = √(a²b), a ≥ 0
If 0 ≤ a < b, then a² < b² and √a < √b
Arrange a = 6, b = 4√2, c = 2√10 in increasing order.
Estimating: between which integers is √50? 49 < 50 < 64 → 7 < √50 < 8; 50 is close to 49, so √50 ≈ 7.07.
[a; b] — closed interval (ends included), (a; b) — open interval, [a; b) — half-open, (a; +∞) — ray
−2 < x ≤ 5 → (−2; 5]. Infinity is not a number and cannot be “reached”, so it always takes a round bracket.
Standard form: a·10ⁿ, 1 ≤ a < 10: 0.000 32 = 3.2·10⁻⁴, 45 000 = 4.5·10⁴.
Rounding: if the first digit dropped is ≥ 5, increase the previous digit by one: 3.1415 ≈ 3.14, 2.718 ≈ 2.72. In practical calculations irrational numbers are always replaced by approximations.
Solving systems and alternatives of inequalities requires the intersection of intervals (∩, numbers in both) and the union (∪, numbers in at least one). The safest way is to draw them on the number line: mark each interval with its own line and read off the common part or the whole coverage.
A system (“and”) — intersection; an alternative (“or”) — union
An important property of the real numbers is density: between any two different numbers there are infinitely many rationals and infinitely many irrationals. For instance, the mean (a + b)/2 lies between a and b.
Find the intersection and union of A = [−2; 5) and B = (1; 7].
Find a rational number between √2 and √3.