In peas, yellow seed colour (A) is completely dominant over green (a) and round seed shape (B) over wrinkled (b); the genes are on different chromosome pairs. A homozygous yellow round plant was crossed with a green wrinkled plant. F₁ plants were intercrossed, giving 1600 F₂ plants. 1) State Mendel’s laws (uniformity, segregation, independent assortment) and the conditions for them (with their cytological basis). 2) Write the P and F₁ crosses, show the F₁ gametes and draw the F₂ Punnett square. 3) Calculate the F₂ phenotypic ratio and the number of plants in each class. 4) Find the number of F₂ plants heterozygous for both genes and the number homozygous for both genes. 5) How many F₂ yellow round plants give no segregation in a test cross? Calculate their share (%) among yellow round plants. For each part, write out the law or method used (cross scheme, formulas, reasoning) and all calculations step by step.
The AI score is an estimate. In the official exam the written part is marked by BMBA examiners.