In humans the ABO blood groups are determined by three alleles of one gene (I⁰, Iᴬ, Iᴮ) and the Rh factor by an autosomal dominant gene (R — Rh-positive, r — Rh-negative); the genes are on different chromosomes. An Rh-positive woman of group II (A) had a father of group I (O) who was Rh-negative. She married an Rh-negative man of group III (B) whose mother was group I (O). 1) Explain multiple allelism and codominance using the ABO system; write the genotypes of each blood group. 2) Determine the spouses’ genotypes with reasons, write the cross and gametes; is there a risk of Rh incompatibility in this family — explain. 3) Calculate the probability (%) of each blood group and of Rh-negativity among the children. 4) Calculate the probability (%) of a group I (O), Rh-negative child. 5) Calculate the probability (%) that two successive children are both group IV (AB) and Rh-positive. For each part, write out the law or method used (cross scheme, formulas, reasoning) and all calculations step by step.
The AI score is an estimate. In the official exam the written part is marked by BMBA examiners.